These are
three possibilities to start a process in Powershell. The goal in this
particular example is to open a text file called “test.txt” under “C:\temp” with
notepad.
First solution
- cmdlet:
start-process
-FilePath "$($env:SystemRoot)\notepad.exe"
-ArgumentList 'C:\temp\test.txt'
Second solution
– dot net:
[System.Diagnostics.Process]::Start("$($env:SystemRoot)\notepad.exe",'C:\temp\test.txt')
Third
solution - wmi:
$process = [wmiclass]'Win32_Process'
$process.Create("$($env:SystemRoot)\notepad.exe
C:\temp\test.txt")
